prev | Implicit if 22. Even number or not (2.7.2009) /* Program# 22 date : 25-12-2008 Even number or not */ #include <stdio.h> main(){ int n,x; printf("\nEnter a integer :"); scanf("%d",&n); x=n%2; if(x) printf("\n%d : Not an Even number\n",n); else printf("\n%d : Even number\n",n); } output: Enter a integer : 13 13 : Not an Even number Things to note: Here the value 1 is considered as true and value 0 as false. Syntax for implicit if if(true) do this; else do this; |
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